How much work is done on a table pulled 5m by a force of 30N at an angle of 60° above the horizontal?
The work done is A=F⋅s⋅cosα=30N⋅5m⋅cos60∘=75JA = F \cdot s \cdot \cos \alpha = 30 N \cdot 5 m \cdot \cos 60^{\circ} = 75 JA=F⋅s⋅cosα=30N⋅5m⋅cos60∘=75J.
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