Answer to Question #178031 in Physics for Suhayb

Question

A particle moves along the x axis. Its position as a function of time is given by

x = 6 . 8 t + 8 . 5 t 2 , where t is in seconds and x is in meters. What is the acceleration as a

function of time?

Answer 1

Let's first find the velocity of the particle:

$$v=\dfrac{dx}{dt}=6.8+17t.$$

Finally, we can find the acceleration of the particle:

$$a=\dfrac{dv}{dt}=17\ \dfrac{m}{s^2}.$$