Question #172841

If the moon has a core with a radius of 400km and the uniform density of the overlying mantle is 3300kgm-3, what is the density of the core, hence calculate the mass of the core.


Expert's answer

The radius of the Moon is 1738 km1738\ km and its mean density is 3347 kg/m33347 \ kg/m^3 . So,


mass of core mc=43πrc3ρcm_c= \frac{4}{3}\pi r_c^3ρ_c


volume of mantle V=43πR343πrc3V=\frac{4}{3}\pi R^3−\frac{4}{3}\pi r_c^3


mass of mantle mm=43π(R3rc3)ρmm_m= \frac{4}{3}\pi (R^3-r_c^3)\rho_m


mass of planet m=mm+mcm=m_m+m_c


43πR3ρ=43π(R3rc3)ρm+43πrc3ρc\frac{4}{3}\pi R^3\rho= \frac{4}{3}\pi (R^3-r_c^3)\rho_m+ \frac{4}{3}\pi r_c^3ρ_c\to


ρρmρcρm=(rcR)333473300ρc3300=(4001738)3\frac{\rho-\rho_m}{\rho_c-\rho_m}=(\frac{r_c}{R})^3\to\frac{3347-3300}{\rho_c-3300}=(\frac{400}{1738})^3\to


ρc7155 kg/m3\rho_c\approx7155\ kg/m^3 . Answer











LATEST TUTORIALS
APPROVED BY CLIENTS