Question

A 50 kg block sits on a level surface. One end of the surface is raised until the block begin to slide down the ramp at a constant velocity. What is the angle if the coefficient friction is 0.750 between the block and the incline plane in degrees?

Answer 1

$mg\sin\alpha-\mu N=ma=0$

$N=mg\cos\alpha$

$mg\sin\alpha=\mu mg\cos\alpha \to \mu=\tan\alpha\to$

$\alpha=\tan^{-1}\mu=\tan^{-1}0.75\approx37°$ . Answer