Question #168954

Proof that v=√T/√M

Where, v=velocity, T=tension and M=mass


1
Expert's answer
2021-03-04T11:35:34-0500

Rewrite the equation according to math rules:


v=TM=TM.v=\frac{\sqrt T}{\sqrt \Mu}=\sqrt{\frac{T}{\Mu}}.


Choose unusual approach. We know that tension is measures in N (newtons), mass per unit length is kg/m (kilograms per metre).

What is a newton?


[N]=[kg][m][s]2.[N]=\frac{[kg]·[m]}{[s]^2}.

Divide this by kg/m:

TM=[kg][m][s]2[m][kg]=[m]2[s]2.\frac{T}{\Mu}=\frac{[kg]·[m]}{[s]^2}·\frac{[m]}{[kg]}=\frac{[m]^2}{[s]^2}.

Now take a square root of this:


[m]2[s]2=m/s.\sqrt{\frac{[m]^2}{[s]^2}}=\text{m/s}.

We see that the velocity is square root of tension divided my linear mass, which is m/s. We know that velocity is measured in m/s, so, we proved that


v=TMv=\frac{\sqrt T}{\sqrt \Mu}


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Comments

Charles
08.03.21, 16:01

Your approach was indeed unusual but thanks a lot

Assignment Expert
08.03.21, 15:51

Dear Charles, s means second

Charles
05.03.21, 16:00

Please, can you tell me what the s stands for

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