Let the mass of the hockey goalie be m1 and the mass of the hockey puck be m2. Let the initial speed of the hockey goalie be u1 and the initial speed of the hockey puck be u2. From the law of conservation of momentum, we have:
m1u1+m2u2=m1v1+m2v2.(1)Since collision is elastic, kinetic energy is conserved and we can write:
21m1u12+21m2u22=21m1v12+21m2v22.(2)Let’s rearrange equations (1) and (2):
m1(u1−v1)=m2(v2−u2),(3)m1(u12−v12)=m2(v22−u22).(4)Let’s divide equation (4) by equation (3):
u1−v1(u1−v1)(u1+v1)=v2−u2(v2−u2)(v2+u2),u1+v1=u2+v2.(5)Let's express v2 from the equation (5) in terms of u1, u2 and v1:
v2=u1−u2+v1.(6)Let’s substitute equation (6) into equation (3). After simplification, we get:
(m1−m2)u1+2m2u2=(m1+m2)v1.From this equation we can find the final speed of the hockey goalie, v1:
v1=(m1+m2)(m1−m2)u1+(m1+m2)2m2u2.
Since, u1=0 (hockey goalie, originally at rest), we get:
v1=(m1+m2)(m1−m2)u1+(m1+m2)2m2u2.v1=(70 kg+0.150 kg)2⋅0.150 kg⋅(−35.0 sm)=−0.150 sm.The sign minus means that the hockey goalie moves to the left after collision.
Substituting v1into the equation (6) we can find the final speed of the hockey puck, v2:
v2=(m1+m2)2m1u1+(m1+m2)(m2−m1)u2,v2=(m1+m2)(m2−m1)u2,v2=(0.150 kg+70 kg)(0.150 kg−70 kg)⋅(−35 sm)=34.9 sm.The sign plus means that the hockey puck moves to the right after collision.
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