Answer to Question #166204 in Physics for gibson mkandawire

Question #166204

1.Turpentine oil is flowing through a tube of length l and radius r. The pressure difference between the two ends of the tube is P. The viscosity of the oil is given by

πœ‚=𝑃(π‘Ÿ2βˆ’ π‘₯2)/4𝑣𝑙

Where v is the velocity of oil at a distance x from the axis of the tube. Determine the dimensions of Ξ·.

2. The position x of a particle depends upon time t according to the equation x = at + bt2. Determine the dimensions and units of a and b. What are the physical quantities denoted by a and b?

3. The velocity v of a particle depends upon time t according to the relation

𝑣=π‘Žπ‘‘+ 𝑏/𝑑+𝑐

What are the dimensions of a, b and c?



1
Expert's answer
2021-03-10T17:22:21-0500

1 We have:

"[\\eta]=\\frac{P(r_2-x_2)}{4vl}=\\frac{\\text{Pa}\u00b7\\text{m}}{\\text{m\/s}\\cdot\\text{m}}=\\\\\\space\\\\\n=\\frac{\\text{Pa}}{\\text{m\/s}}=\\frac{\\text{kg}}{\\text{m}^2\\text{s}}=\\text{N}\u00b7\\text{s}\/\\text{m}^2."

2 The physical quantities denoted by a and b are initial velocity and acceleration: x is in meters, so


"\\text{m}=[a]\u00b7\\text{s},\\\\\n[a]=\\text{m\/s}.\\\\\n\\text{m}=[b]\u00b7\\text{s}^2,\\\\\n[b]=\\text{m\/s}^2."

3 Same approach as in (2):


"\\text{m\/s}=[a]\u00b7\\text{s},\\\\\n[a]=\\text{m\/s}^2.\\\\\n\\text{m\/s}=[b]\/\\text{s},\\\\\n[b]=\\text{m}.\\\\\n\\text{m\/s}=[c]."

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