Four forces, 60N at 60o and 50N at 30o both clockwise, 40N due north – west and 30N south – west, act at the origin. Calculate the magnitude and direction of the resultant force.
"F_x=-40\\cdot\\cos45\u00b0-30\\cdot\\cos45\u00b0+50\\cdot\\sin30\u00b0+60\\cdot\\sin60\u00b0="
"=52\\ (N)"
"F_y=40\\cdot\\sin45\u00b0-30\\cdot\\sin45\u00b0+50\\cdot\\cos30\u00b0+60\\cdot\\cos60\u00b0="
"=80.4\\ (N)"
"F=\\sqrt{52^2+80.4^2}=96\\ (N)" . Answer
"\\alpha=\\tan^{-1}\\frac{80.4}{57.1}=57.1\u00b0" North of East . Answer
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