Answer to Question #166201 in Physics for gibson mkandawire

Question #166201

1.Determine the value of a so that vector 𝑨⃗⃗ =(𝟏𝟎𝒊̂+𝟏𝟒𝒋̂−𝟔𝒌̂) is perpendicular to vector 𝑨⃗⃗ =(𝟏/𝟐𝒊̂+𝟏/𝟐𝒋̂+𝒂𝒌̂)

2. A particle covers a distance of (𝟐𝒊̂+𝟑𝒋̂+𝟓𝒌̂) metres in the direction of a constant force of (𝟕𝒊̂+𝟖𝒋̂+𝟑𝒌̂) newtons acting on it. Calculate the work done by the force on this particle.

3. A body moves from position (𝟐𝒊̂+𝟐𝟎𝒋̂−𝟏𝟖𝒌̂) metres to a position

(𝟏𝟔𝒊̂+𝟐𝟒𝒋̂+𝟏𝟓𝒌̂) metres when a force of (𝟒𝒊̂+𝟐𝒋̂+𝟑𝒌̂) newton is applied on it. Calculate the work done on a body.

4. A point of application of a force 𝑭⃗⃗ =(𝟏𝟔𝒊̂+𝟐𝟎𝒋̂+𝟏𝟓𝒌̂) is moved from

𝒓𝟏⃗⃗⃗⃗ =(𝟐𝒊̂+𝟕𝒋̂+𝟐𝒌̂) to 𝒓𝟐⃗⃗⃗⃗ =(𝟓𝒊̂+𝟏𝟐𝒋̂+𝟑𝒌̂). Find the work done.


1
Expert's answer
2021-03-09T15:30:52-0500

1)


"(10,14,-6)\\cdot(0.5,0.5,a)=5+7-6a=0\\\\a=2"

2)


"W=Fr=(2,3,5)\\cdot(7,8,3)\\\\=14+24+15=53\\ J"

3)


"\\Delta r=(16,24,15)-(2,20,-18)=(14,4,33)\\ m"


"W=F\\Delta r=(4,2,3)\\cdot(14,4,33)=163\\ J"

4)


"\\Delta r=(5,12,3)-(2,7,2)=(3,5,1)\\ m"

"W=F\\Delta r=(16,20,15)\\cdot(3,5,1)=163\\ J"


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