Question #162539

A charge emanates an electric field of 7 N/C. If this field is placed on a rhombus surface that has a side 

length of 5mm and one of its angles is 60o

and is angled 60o from the surface, what is the electric flux?


1
Expert's answer
2021-02-11T08:54:59-0500

Find area of the rhombus:


A=d2 sinθ.A=d^2 \text{ sin}\theta.


The flux is


Φ=EA sinθ=E(d sinθ)2=1.31104 N m2/ C.\Phi=EA\text{ sin}\theta=E(d\text{ sin}\theta)^2=1.31\cdot10^{-4}\text{ N m}^2/\text{ C}.


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