Determine the radius of a shift in decimeter of a pulley rotating at 300 revolution per minute when it drives another shaft rotation at 800 revolution per minutes having a diameter of 0.2m
The velocity "v" of the point of contact on the pitch circles is the same on both gears, and is given by
"v=r_1\\omega_1=r_2\\omega_2"
So,
"\\frac{r_1}{r_2}=\\frac{\\omega_2}{\\omega_1}\\to\\frac{r_1}{r_2}=\\frac{n_2}{n_1}\\to r_1=r_2\\frac{n_2}{n_1}="
"=0.2\\cdot\\frac{800}{300}\\approx0.53\\ (m)" . Answer
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