A 0.1 kg hockey puck, initially moved at 5 m/s, slides a distance of 50 meters across a horizontal ice surface and comes to a stop due to some friction
Find the coefficient of friction.
Ff=ma→μN=ma→μmg=ma→μ=agF_f=ma\to\mu N=ma\to \mu mg=ma\to \mu=\frac{a}{g}Ff=ma→μN=ma→μmg=ma→μ=ga
s=v2−v022a→a=v2−v022s=52−022⋅50=0.25(m/s2)s=\frac{v^2-v_0^2}{2a}\to a=\frac{v^2-v_0^2}{2s}=\frac{5^2-0^2}{2\cdot 50}=0.25(m/s^2)s=2av2−v02→a=2sv2−v02=2⋅5052−02=0.25(m/s2)
μ=0.259.8=0.026\mu=\frac{0.25}{9.8}=0.026μ=9.80.25=0.026 . Answer
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