Question #161412

A Slinky has a k-value of 0.80 kg/s2.  If it is stretched to 2.7 meters, what is its elastic potential energy?


1
Expert's answer
2021-02-05T02:13:47-0500
PEelastic=12kx2,PE_{elastic}=\dfrac{1}{2}kx^2,PEelastic=120.8 kgs2(2.7 m)2=2.92 J.PE_{elastic}=\dfrac{1}{2}\cdot 0.8\ \dfrac{kg}{s^2}\cdot(2.7\ m)^2=2.92\ J.

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