Question

A stone is thrown from the top of a building TT toward another building 50m away. The initial velocity of the stone is 20m/s, at 400 above horizontal. How far above or below its original level will the ball strike the opposite wall?

Answer 1

$v_{x0}=20\cdot\cos40°=15.32(m/s)$

$v_{y0}=20\cdot\sin40°=12.86(m/s)$

The stone flight time

$t=50/15.32=3.264(s)$

$y=v_{y0}t-gt^2/2=12.86\cdot 3.264-9.8\cdot3.264^2/2=-10.23(m)$

$10.23\ (m)$ below its original level. Answer