Question

A guage records the pressure of a tire as 160000Nm/2. Assuming the volume is unchange, what does the guage read at 30degrees clesius ? The reading ona Tyre reads the pressure above atmospheric pressure. The atmosphere pressure can be assumed to be 100000Nm/2

Answer 1

$$P_2=P_1\frac{T_2}{T_1}\\P_2^g+P_a=(P_1^g+P_a)\frac{T_2}{T_1} \\P_2^g+100000=(160000+100000)\frac{273+30}{273}\\P_2^g=190000\ Pa$$