Question

The only force acting on a 5kg object has components Fx=20N and Ft=30N. Find the magnitude and directions of the acceleration of the object.

Answer 1

$a_x=F_x/m=20/5=4(m/s^2)$

$a_y=F_y/m=30/5=6(m/s^2)$

$a=\sqrt{4^2+6^2}=7.21(m/s^2)$ . Answer

$\tan\alpha=6/4=1.5\to \alpha=56.3°$ from the positive direction of the x-axis. Answer