The only force acting on a 5kg object has components Fx=20N and Ft=30N. Find the magnitude and directions of the acceleration of the object.
"a_x=F_x\/m=20\/5=4(m\/s^2)"
"a_y=F_y\/m=30\/5=6(m\/s^2)"
"a=\\sqrt{4^2+6^2}=7.21(m\/s^2)" . Answer
"\\tan\\alpha=6\/4=1.5\\to \\alpha=56.3\u00b0" from the positive direction of the x-axis. Answer
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