Given that the mass of the crate is 32 kg and the coefficient of static friction between the crate and the floor is 0.57, the horizontal force required to start the crate moving is
"F_H=F\\text{ cos}21\u00b0=\\mu N,\\\\\nN=mg+F\\text{ sin}21\u00b0,\\\\\nF\\text{ cos}21\u00b0=\\mu mg+F\\text{ sin}21\u00b0,\\\\\\space\\\\\nF=\\frac{\\mu mg}{\\text{cos}21\u00b0-\\text{sin}21\u00b0}=311\\text{ N}."The acceleration of the crate if the applied force is 330 N and the coefficient of kinetic friction is 0.45 can be determined from the following condition by Newton's second law:
"ma=F\\text{ cos}21\u00b0-\\mu N,\\\\\nN=mg+F\\text{ sin}21\u00b0,\\\\\nma=F\\text{ cos}21\u00b0-\\mu(mg+F\\text{ sin}21\u00b0),\\\\\\space\\\\\na=\\frac{1}{m}[F\\text{ cos}21\u00b0-\\mu(mg+F\\text{ sin}21\u00b0)]=7.5\\text{ m\/s}^2."
Comments
Leave a comment