Question #140921

Fighter Jet pilots can be subjected to quite large forces during flight maneuvers. A 80 kg pilot is flying in a swooping arc, down and then up, with a radius of 500m and a speed of 140 m/s. What is the normal force of the seat on the pilot when she is at the lowest point of the arc?

Expert's answer

N=mg+mv2rN=(80)(9.8)+801402500=3920 NN=mg+m\frac{v^2}{r}\\N=(80)(9.8)+80\frac{140^2}{500}=3920\ N


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