Question

What is the amount of power applied by the wind glass to a 20kg anchor if
it is lifted 2-m high within 5s?

Answer 1

By definition, the power is:

$$P = Fv$$

where $v = \dfrac{2m}{5s} = \dfrac{2}{5}m/s$ is the speed of anchor and $F = mg = 20kg\cdot 9.81m/s^2 = 196.2N$ is the force applied to it. Thus, obtain:

$$P = Fv = \dfrac{2}{5}\cdot 196.2 = 78.48W$$

Answer. 78.48 W.