Answer to Question #140913 in Physics for Raffy

Question

Calculate the work done of the lady on
the lawnmower. Whereas, Force (F) =
48N , Displacement (d) = 8.5m and
theta (θ) = 35°.

Answer 1

The work is force times displacement in the direction of force action, i.e. additionally we multiply the product of force and displacement by the cosine of the angle between them:

$$W=Fd\text{ cos}\theta=48\cdot8.5\cdot\text{cos}35°=334\text{ J}$$