"4.0in=10.16cm"
"1.50in=3.81cm"
"V=\\frac{\\pi d^2}{4}h=\\frac{3.14\\cdot 3.81^2}{4}\\cdot10.16\\approx116(cm^3)"
"\\rho=m\/V=100.0\/116=0.862(g\/cm^3)"
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