"4in=10.16cm"
"1.50in=3.81cm"
"V=\\pi r^2h=\\pi(\\frac{d}{2})^2h=3.14\\cdot(\\frac{3.81}{2})^2\\cdot 10.16\\approx 116(cm^3)"
"\\rho=m\/V=100.0\/116=0.862(g\/cm^3)"
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