The Reynold’s number for the cylindrical pipe is given by the following expression:
Re=AμQDρ where Q=4m3/s is the volumetric flow rate, D=0.06m is the pipe diameter, A=πD2/4 is the pipe's cross-sectional area, ρ=1268kg/m3 is a density and μ=17Pa⋅s is is the dynamic viscosity.
Substituting this values to the equation, get:
Re=πD2μ4QDρ=πDμ4Qρ=π⋅0.06⋅174⋅4⋅1268≈6331 A flow can be considered as turbulent if Re>2900. Thus, this flow is turbulent.
Answer. Re = 6331, turbulent.
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