Answer to Question #123868 in Physics for jax

Question

A truck heading east has an initial velocity of 6 m/s. It accelerates at 2 m/s2 for 12 seconds. What distance does the truck travel in the given time?

Answer 1

The kinamatic law for the uniform acceleration is the following:

$$d = v_0t + \dfrac{at^2 }{2}$$

Here $d$ is the distance traveled by the truck, $a$ is its acceleration and $t$ is time.

Substituting numerical values, get:

$$d = 6m/s\cdot 12s+\dfrac{2m/s^2\cdot 12^2s^2}{2} = 216 m$$

Answer. d = 216m