Answer to Question #113581 in Physics for Lauren

Question #113581
What is the DISTANCE between a 20 kg cannonball and a 0.01 kg marble if the gravitational attraction between a 20 kg cannonball and a marble is 0.48 x 10^-10 N?
1
Expert's answer
2020-05-04T12:41:29-0400

According to Newton's law of gravitation, gravitational force between two objects of mass m1,m2m_1, m_2, located at distance RR between each other is F=Gm1m2R2F = \frac{G m_1 m_2}{R^2}, where G=6.6741011m3kg1s2G = 6.674 \cdot 10^{-11} m^3 kg^{-1} s^{-2} is the universal gravitational constant.

Using the last formula, the distance between the cannonball and marble is:R=Gm1m2F=6.671011m3kg1s220kg0.01kg0.481010N0.53mR = \sqrt{\frac{ G m_1 m_2}{F}} = \sqrt{\frac{6.67 \cdot 10^{-11} m^3 kg^{-1} s^2 \cdot 20 kg\cdot 0.01 kg}{0.48 \cdot 10^{-10} N}} \approx 0.53 m


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