Answer to Question #113578 in Physics for Mohammed Al-fatlawi

Question

A different constant velocity cart travelled 0.980.01 m in 4.20.1s.

Calculate the speed that the car traveled, including uncertainty. Show and explain ALL your working.

Answer 1

The speed:

$$v=\frac{s}{t}=\frac{0.98}{4.2}=0.233\frac{m}{s}$$

Uncertainty:

$$\frac{\Delta v}{v}=\frac{\Delta s}{s}+\frac{\Delta t}{t}=\frac{0.01}{0.98}+\frac{0.1}{4.2}=0.034$$

$$\Delta v=(0.034)(0.23)=0.008\frac{m}{s}$$