Question

Two protons are separated by a distance of 2.0×10-15. What is the magnitude of the electric force between them

Answer 1

$$F=k\frac{e^2}{r^2}=(9\cdot 10^{9})\frac{(1.6\cdot 10^{-19})^2}{(2\cdot 10^{-15})^2}=58\ N$$