Answer to Question #108164 in Physics for Mukelo Madolo

Question #108164
the quantity of charge q (in coulombs) that has passed through a surface of area 2.00 cm^2 varies with time according to the equation q=4t^3 + 5t+6 , where t is in seconds.a)what is the instantaneous current through the surface at t=1.00 s? b)what is the value of the current density?
1
Expert's answer
2020-04-09T09:34:28-0400

a)


I=dqdt=4(3t2)+5=12t2+5I=\frac{dq}{dt}=4(3t^2)+5=12t^2+5

I(1)=12(1)2+5=17 AI(1)=12(1)^2+5=17\ A

b)


J(1)=I(1)A=172104=85000Am2J(1)=\frac{I(1)}{A}=\frac{17}{2\cdot 10^{-4}}=85000\frac{A}{m^2}


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