A 0.67 kg spike is hammered into a railroad
tie. The initial speed of the spike is equal to
3.3 m/s.
If the tie and spike together absorb 75.1
percent of the spike’s initial kinetic energy
as internal energy, calculate the increase in
internal energy of the tie and spike.
Answer in units of J.
K=0.5mv2
ΔE=0.751K=0.751(0.5)(0.67)(3.3)2=2.74 J
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