The volume change of the mercury is
and it should be equal to the mercury volumein the tube, since we ignore the expansion of the glass
"\\pi r^2\u2206h=\\frac{4\\pi R^3}{3}\u03b2 \u2206T"
"(0.00185)^2\u2206h=\\frac{4 (0.14)^3}{3}(0.000182)(41)"
"\u2206h=7.98\\ cm"
Comments
It gives you the correct answer.
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