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How to find the refractive index of glass when wavelength of light=650, angle of refraction=28.1, speed of light in air=1c and speed of light in glass=.67c.
Using the appropriate figure, estimate the total chromatic dispersion at 1550 nm of a step-index figure having a core radius of 3 um.
As light passes into the eye, muscles will change the shape of the lens within the eye to ensure the rays are focused onto the retina (Fig A). The lens and cornea together can be approximated by one thin lens with an effective focal length (Fig B). For parallel rays coming from some distant object, the eye will not need to change the shape of the lens from its natural shape for the rays to be focused. The rays emitted from closer objects will not be parallel and the lens must change shapes. (a) When the eye is at rest looking at a distant object, its focal length is 2.50 cm. If the object is moved to 0.4 meters away from the eye, what must the new focal length be in order for the eye to see the object clearly. (b) Are the muscles within the eye flattening the lens or adding additional curvature to it to create the new focal length?
Consider the thin lenses in the drawing (n= 1.55). Suppose that for each of them R1= 25 cm and R2= 60 cm. 1) Find the focal lengths for each lens, and use their signs to obtain the location of the image of a distant source. 2) For each lens, is the image upright or inverted, virtual or real? 3) Calculate the magnification, and check that it agrees with your answer to the previous question.
Consider the following two waves expressed in SI units: E_x=8sin(ky-ωt+π/2) and E_z=8sin(ky-ωt). Which wave leads, and by how much? Describe the resultant wave. What is the value of its amplitude?
If diameter of human eye is 2.5cm, find the power range of the eye
The equation connecting s, p, and f for a simple lens can be employed for spherical mirrors, too. A concave mirror with a focal length of
3 cm
forms an image of a small object placed
11 cm
in front of the mirror. Where will this image be located? (For spherical mirrors, positive p means the image is on the same side of the mirror as the object.)
p =
A person struggles to read by holding a book at arm’s length, a distance of 52 cm away. What power of reading glasses should be described for her if she wants to read at the “normal” near point of 25 cm? Assume the lens is very close to the eye.
The numerical aperture of an optical fiber is 0.39. If the difference in the refractive indices of the material of its core and cladding is 0.05, calculate the refractive index of material of the core.
An object is placed 20.0 cm from a converging lens with focal length 15.0 cm (see the figure, not drawn to scale). A concave mirror with focal length 10.0 cm is located 78.5 cm to the right of the lens. Light goes through the lens, reflects from the mirror, and passes through the lens again, forming a final image.
What is the overall transverse magnification?