Question

The equation connecting s, p, and f for a simple lens can be employed for spherical mirrors, too. A concave mirror with a focal length of
3 cm
forms an image of a small object placed
11 cm
in front of the mirror. Where will this image be located? (For spherical mirrors, positive p means the image is on the same side of the mirror as the object.)
p =

Answer 1

$$\frac{1}{p}+\frac{1}{s}=\frac{1}{f}$$

$$\frac{1}{p}+\frac{1}{11}=\frac{1}{3}$$

$$p=4.125\ cm$$