Question #113352
the image of a crayon appears to be 22.8 cm behind the surface of a convex mirror and is 3.38 cm tall. The mirrors focal length is 51.2 cm (a) how far in front of the mirror is the crayon positioned?
1
Expert's answer
2020-05-04T12:48:02-0400

As per the question,

Image position from the convex mirror (v)=22.8cm(v)=22.8cm

Height of the image (hi)=3.38cm(h_i)=3.38 cm

The mirror of the focal length (f)=51.2cm(f)=51.2cm

distance of the object from the convex mirror=?

Let it is at a distance u.

Now, applying the mirror formula,

1v+1u=1f\dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}

1u=1f1v\Rightarrow \dfrac{1}{u}=\dfrac{1}{f}-\dfrac{1}{v}

1u=151.2122.8\Rightarrow \dfrac{1}{u}=\dfrac{1}{51.2}-\dfrac{1}{22.8}

u=41.10cm\Rightarrow u=-41.10cm

Height of the object

vu=hiho\dfrac{-v}{u}=\dfrac{h_i}{h_o}

ho=uv×hi=41.1022.8×3.38cm=6.084cmh_o=-\dfrac{u}{-v}\times h_i=\dfrac{41.10}{22.8}\times 3.38 cm=6.084cm


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