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Optics
A point source of light ‘o’ is placed at the principal axis of a bi-convex lens and the image is formed at ‘I’. If a plane mirror is placed perpendicular to the principal axis at ‘I’, the final image ( 1 ) is real and at the I.
( 2 ) is real and at the o.
( 3 ) is real and at the focus of the lens.
( 4 ) is virtual and at the I.
( 5 ) is virtual and behind the mirror.
( 2 ) is real and at the o.
( 3 ) is real and at the focus of the lens.
( 4 ) is virtual and at the I.
( 5 ) is virtual and behind the mirror.
Optics
A boy 115cm in height is standing at a distance of 65cm from a vertical mirror 50cm in length, the upper edge of which is 125cm from the floor. Talking the boy's eye level to be 98cm above the floor, determine with the help of a diagram
a) how much of his height will be seen by him in the mirror
b) what length of the mirror is useful to him
Optics
What is diffraction grating? Explain the intensity distribution
Optics
An old person cannot see objects closer than 200 cm from his eye. Determine the lens he should wear to view objects at 25 cm from his eye.
5 Leel Ashokarathne
If the rays converging at a point not less than 150 cm behind the eye lens can be focused by the eye, find the visual range with spectacles.
5 Leel Ashokarathne
If the rays converging at a point not less than 150 cm behind the eye lens can be focused by the eye, find the visual range with spectacles.
Optics
The distance between the eye lens and retina of an eye is 2.6 cm. The eye can see far objects comfortably. The near point is at 31.2 cm. Find the distance by which the focal length of the eye can be adjusted.
Optics
A multimode fiber has a core diameter of 70 micro meter and relative refractive index difference of 1.5%. It operates at the wavelength of 0.85mm. The refractive index of the fibre is 1.46. Calculate the refractive index of the cladding and normalised frequency V number of fiber.
Optics
Consider the lens equation (1) for a convex (converging) lens. If you were to determine where an image is formed for an object very, very far away, like the sun, an approximate relationship between the image length and the focal point can be derived. By looking up the
distance from the earth to the sun to assist you, derive this relationship. Remember to reference properly
distance from the earth to the sun to assist you, derive this relationship. Remember to reference properly
Optics
3. Consider an object which is 0.700 m high, placed 2.00 m in front of a concave (diverging) lens with focal point 0.500 m. Draw a scale diagram of the object and the lens. Clearly indicate at least two rays from the object that strike the lens. Make sure you indicate your chosen scale in the drawing. Include a picture of your drawing! Determine the image length and image height, and describe the image formed. DO NOT use the lens equations
Optics
When a converging lens is placed between an object and a screen , an image of height 4 cm is produced on the screen. Without changing the distance between the object and the screen , another image of height 16 cm is produced on the screen at another position of the lens. Find the height of the object.
Optics
An object ‘o’ , a converging lens L of focal length 15 cm and concave mirror M are placed.the object distance is 30 cm, while the distance between lens and mirror is 50 cm. If the object and the final image coincide , the focal length of M is,
( 1 ) 10 cm ( 2 ) 15 cm ( 3 ) 20 cm ( 4 ) 25 cm ( 5 ) 30 cm
( 1 ) 10 cm ( 2 ) 15 cm ( 3 ) 20 cm ( 4 ) 25 cm ( 5 ) 30 cm
