Question #141229
A multimode fiber has a core diameter of 70 micro meter and relative refractive index difference of 1.5%. It operates at the wavelength of 0.85mm. The refractive index of the fibre is 1.46. Calculate the refractive index of the cladding and normalised frequency V number of fiber.
1
Expert's answer
2020-11-02T07:09:24-0500

Total number of modes in a multimode fiber is given by


M=12[πdλ.NA]2M=\frac {1}{2}[\frac{\pi d}{\lambda}.NA]^2


d is the diameter


d=1.3×1062×1100π×0.21213d= \frac {1.3\times10^{-6}\sqrt2\times1100}{\pi \times 0.21213}


m=91.5μmm=91.5\mu m


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