1f=1v+1u\frac{1}{f} = \frac{1}{v}+\frac{1}{u}f1=v1+u1
115=1v+130\frac{1}{15} = \frac{1}{v}+\frac{1}{30}151=v1+301
1v=115+130=110\frac{1}{v} = \frac{1}{15} + \frac{1}{30} = \frac{1}{10}v1=151+301=101
v = 10 cm
d = v +2f
50 = 10 + 2f
40 = 2f
f = 20 cm
Answer: (3) 20 cm
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