From the lens equation we know that;
"\\frac{1}{v}+\\frac{1}{u}=\\frac{1}{f}"
As per the conditions of the question,
the object is too far hence we will consider "u=\u221e"
in this case we rewrite the equation as ;
"\\frac{1}{v}+\\frac{1}{\u221e}=\\frac{1}{f}"
or
"\\frac{1}{v}=\\frac{1}{f}"
therefore, "v=f"
Formation of the long distant object will take place at the focal point of the lens.
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