A square ABCD of side 1mm is kept at distance 15cm infront of the concave mirror . The focal length of the concave mirror is 10cm . The length of the perimeter of its image will be (1)8mm. (2) 2mm (3)12mm (4)6 mm
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Heena
02.06.19, 07:40
Given :-side =1mm=.1cm,U=-15cm,f=-10cm I/f =1/U+1/V= -30cm
HI/HO=-V/U=-2mm we need to neglect -ve sign now dist of image also
matter -2mm belong y axis so we find x axis dist:- dV/dU=-(V/U)square
=-4mm =-.4cm here we also neglect -ve sign now:-
Perimeter:-4*2+2*2=8+4=12mm or (4+2)*2=12mm=.12cm
Assignment Expert
22.03.18, 17:34
Dear Naveen, answer is correct
Naveen
22.03.18, 16:57
Sir thanks for solving but correct answer is 12mm so can you please
check it again!!!!!!!?????
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Comments
Given :-side =1mm=.1cm,U=-15cm,f=-10cm I/f =1/U+1/V= -30cm HI/HO=-V/U=-2mm we need to neglect -ve sign now dist of image also matter -2mm belong y axis so we find x axis dist:- dV/dU=-(V/U)square =-4mm =-.4cm here we also neglect -ve sign now:- Perimeter:-4*2+2*2=8+4=12mm or (4+2)*2=12mm=.12cm
Dear Naveen, answer is correct
Sir thanks for solving but correct answer is 12mm so can you please check it again!!!!!!!?????
Leave a comment