Question

A trough 12.0cm deep is filled with water of refractive index 4/3 how much would a coin at the bottom of trough appear to be displaced when viewed vertically from above the water surface

Answer 1

Answer on Question #73854-Physics-Optics

A trough 12.0cm deep is filled with water of refractive index 4/3 how much would a coin at the bottom of trough appear to be displaced when viewed vertically from above the water surface

Solution

Real depth is H. Apparent depth is h.

$$n = \frac {H}{h}$$ $$\frac {4}{3} = \frac {12}{h}$$ $$h = \frac {12}{4} \cdot 3 = 9 \text{ cm}.$$

Therefore,

$$H - h = 12 - 9 = 3 \text{ cm}.$$

Answer: 3 cm.

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