Question

What was the original far point of a patient who had laser vision correction to reduce the minimum power of her eye by 4.25 diopters, producing normal distant vision for her? Assume a distance from the eye lens to the retina of 2.00 cm, so the minimum power for normal vision is 50.0 diopters.

Answer in cm

Answer 1

Answer on Question #56237-Physics-Optics

What was the original far point of a patient who had laser vision correction to reduce the minimum power of her eye by 4.25 diopters, producing normal distant vision for her? Assume a distance from the eye lens to the retina of 2.00 cm, so the minimum power for normal vision is 50.0 diopters.

Solution

The initial power is

$$P = P _ {n o r m} + 4. 2 5 \mathrm {D} = 5 0. 0 \mathrm {D} + 4. 2 5 \mathrm {D} = 5 4. 2 5 \mathrm {D}$$ $$P = \frac {1}{d _ {o}} + \frac {1}{d _ {i}} \rightarrow d _ {o} = \frac {d _ {i}}{P d _ {i} - 1} = \frac {0 . 0 2}{5 4 . 2 5 \cdot 0 . 0 2 - 1} = 0. 2 3 5 m = 2 3. 5 c m.$$

Answer: 23.5 cm.

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