Answer to Question #95933 in Molecular Physics | Thermodynamics for Chukwu Sunday

Question

The volume of a gas is doubled at constant pressure initially at 87c,calculate the new temperature

Answer 1

We can use ideal gas law. Let's write it for the first state (before expansion)

$$pV = \nu RT$$

Now we can write it for the second state (we know that ${p_2} = p$ and ${V_2} = 2V$ )

$$2pV = \nu R{T_2}$$

Using first equation we get

$$2\nu RT = \nu R{T_2}$$

Thus

$${T_2} = 2T = 2 \cdot 87[^\circ {\text{C}}] = 174[^\circ {\text{C}}]$$

This is the answer but if we want we can express the temperature in SI unit

$${T_2} = 174[^\circ {\text{C}}] \approx 447.15[{\text{K}}]$$