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Answer to Question #95765 in Molecular Physics | Thermodynamics for atieq khan
Question #95765
0.05 m^3 of gas at 6.9 bar expands reversibly in a cylinder behind the piston according to law pv = constant until the volume is 0.08 m^3. calculate the work done by gas.
Expert's answer
Work Done = "PdV" , dV is the volume change
P = 6.9 bar = 6.809 atm
= 6.809 * (0.08-0.05)
= 0.20 J
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