Question

0.05 m^3 of gas at 6.9 bar expands reversibly in a cylinder behind the piston according to law pv = constant until the volume is 0.08 m^3. calculate the work done by gas.

Answer 1

Work Done = $PdV$ , dV is the volume change

P = 6.9 bar = 6.809 atm

= 6.809 * (0.08-0.05)

= 0.20 J