Question #48540

A copper cup holds some cold water at 4 C. The copper cup weighs 140g while the water weighs 80g. If 100g of hot water, at 90 C is added, what will be the final temperature of the water?
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Expert's answer

2014-11-04T11:20:05-0500

Answer on Question #48540 – Physics – Molecular Physics | Thermodynamics

1. A copper cup holds some cold water at 4 C. The copper cup weighs 140g while the water weighs 80g. If 100g of hot water, at 90 C is added, what will be the final temperature of the water?



Let evaluate the quantity:


T = \frac{0.1 \cdot 385 \cdot 363 + (0.14 \cdot 385 + 0.08 \cdot 4200) \cdot 277}{(0.1 + 0.14) \cdot 385 + 0.08 \cdot 4200} = 284.7\,K = 11.7\,^{0}C.


Answer: 11.7\,^{0}C

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Comments

Assignment Expert
08.07.20, 17:01

Dear Tusharika, final temperature for all system is T

Tusharika
07.07.20, 17:35

Why here in case of heat loss equation ,(90-T) is done ..?does this mean that for water with 100g ,we r taking its initial temp. to be T nd final as 90℃ as by the formula mc(T2 - T1)

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