Question #48417

A closed cylinder vessel contain N moles of an ideal diatomic gas at at constant temperature T.on supplying heat,temperature remains same but 'n' moles get dissociated into atoms.the heat supplied is....
1

Expert's answer

2014-10-31T14:28:38-0400

Answer on Question #48417, Physics, Molecular Physics | Thermodynamics

A closed cylinder vessel contains N moles of an ideal diatomic gas at constant temperature T. On supplying heat, temperature remains same but 'n' moles get dissociated into atoms. The heat supplied is...

Solution:

Since the gas is enclosed in a vessel, therefore, during heating process, volume of the gas remains constant. Thus, no work is done by the gas. It means heat supplied to the gas is used to increase its internal energy only.

Initial internal energy of the N moles of diatomic gas is


U1=N52RTU _ {1} = N \frac {5}{2} R T


Since n moles get dissociated into atoms, therefore, after heating, vessel contains (N - n) moles of diatomic gas and 2n moles of a mono-atomic gas. Hence the internal energy for the gas, after heating, will be equal to


U2=(Nn)52RT+2n32RT=52NRT+12nRTU _ {2} = (N - n) \frac {5}{2} R T + 2 n \frac {3}{2} R T = \frac {5}{2} N R T + \frac {1}{2} n R T


Thus, the heat supplied is equal to the increase in internal energy


Q=U2U1=52NRT+12nRT52NRT=12nRTQ = U _ {2} - U _ {1} = \frac {5}{2} N R T + \frac {1}{2} n R T - \frac {5}{2} N R T = \frac {1}{2} n R T


Answer: Q=12nRTQ = \frac{1}{2} nRT

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Comments

Assignment Expert
07.11.17, 18:42

A_2 -> 2A Thus one mol of diatomic gas dissociates into two moles of monoatomic

Afruza Begum
07.11.17, 18:21

Where from 2n moles of monoatomic gas came?

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