Question #48416

To an ideal tri atomic gas 800cal heat energy is supplied at constant pressure.if vibrational mode is neglected, then energy used by as in work done against surrounding is
A) 200cal. B) 300cal. C) 400cal. D) 60cal

Expert's answer

Answer on Question #48416, Physics, Molecular Physics | Thermodynamics

To an ideal triatomic gas 800cal heat energy is supplied at constant pressure. If vibrational mode is neglected, then energy used by as in work done against surrounding is

A) 200cal. B) 300cal. C) 400cal. D) 60cal

Solution:

According to the first law of thermodynamics,


Q=ΔUWQ = \Delta U - W


where ΔU\Delta U is the change in the internal energy of the system and WW is work done by the system. The work is


W=PΔV=ΔUQW = P \Delta V = \Delta U - Q


Initial internal energy of the N moles of diatomic gas is


U1=N62RT1U_1 = N \frac{6}{2} R T_1


The internal energy for the gas, after heating, will be equal to


U2=N62RT2U_2 = N \frac{6}{2} R T_2


Thus,


ΔU=U2U1=N62R(T2T1)=62PΔV=3PΔV=3W\Delta U = U_2 - U_1 = N \frac{6}{2} R (T_2 - T_1) = \frac{6}{2} P \Delta V = 3 P \Delta V = 3 W


Hence,


W=3WQW = 3 W - QW=Q2=400 calW = \frac{Q}{2} = 400 \text{ cal}


Answer: C) 400cal.

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