Question #278458

A bird is flying with a speed of 16.8 m/s over water when it accidentally drops a 2.50 kg fish.

The acceleration of gravity is 9.81 m/s2 .

If the altitude of the bird is 6.20 m and air resistance is disregarded, what is the speed of the fish when it hits the water?

Answer in units of m/s.


1
Expert's answer
2021-12-13T11:08:06-0500

V=16.8m/secm=2.50kgg=9.81m/sec2h=6.20mV=16.8m/sec\\m=2.50kg\\g=9.81m/sec^2\\h=6.20m


Machanicalenergy(ME)=12mv2+mghMachanical energy ( ME)=\frac{1}{2}mv^2+mgh

ME=12×2.50×16.82+2.50×9.81×6.20ME=\frac{1}{2}\times2.50\times16.8^2+2.50\times9.81\times6.20

ME =352.8+152.055=504.855J

E=504.855J

V=2EmV=\sqrt {\frac{2E}{m}}

V=2×504.8552.50V=\sqrt{\frac{2\times504.855}{2.50}}

V=20.09m/secV=20.09m/sec


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