Solution;
Given;
m˙=1lb/s=0.454kg/s
P1=300atm=303.975MPa
T1=450°R=222.222K
P2=30atm=303.975×104Pa
Ideal gas;
T1T2=(P1P2)kk−1
For air,k=1.4
T2=222.222(303.975×106303.975×104)1.40.4=59.615K
Work;
W=mcv(T2−T1)
W=0.454×718(222.222−59.615)=530005.2J/s=53.00kW
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