a rigid tank holds 4 kg of water at 20 degree Celcius. If 200 kJ of heat is added to this system, what will be the final temperature? how much work is done in this process
Q = heat
m = mass of water
u1 = the initial specific internal energy
u2 = the final specific internal energy for liquid
From the Table C-1 of “Properties of Saturated H2O-Temperature table” for initial temperature
T1 = 20 °C , note the initial specific internal energy u1 = 83.9 kJ/kg
m= 4 kg
Q = 200 kJ
From the Table C-1 of “Properties of Saturated H2O-Temperature table” for final specific internal energy u2 = 134 kJ/kg note the final temperature T2 = 32 °C
The final temperature is 32 °C
Since the container is rigid one and there is no possible for work done.
W=0
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