Answer to Question #264373 in Molecular Physics | Thermodynamics for Reign

Question

determine the sea level specific weight in lbf/cubic feet of liquid of density of 1.75 per cubic feet

Answer 1

We know that 1 kg/m³ = 0.00194032 slug/ft³

$\frac{1.75}{0.00194032} = 901.91 \;kg/m^3$

Now we also know that 1 kg/m³ = 0.062428 lb/ft³

$901.91 \times 0.062428 = 56.30 \;lb/ft^3$

Answer: 56.30 lb/ft³