Question #264373

determine the sea level specific weight in lbf/cubic feet of liquid of density of 1.75 per cubic feet


1
Expert's answer
2021-11-14T17:14:45-0500

We know that 1 kg/m3 = 0.00194032 slug/ft3

1.750.00194032=901.91  kg/m3\frac{1.75}{0.00194032} = 901.91 \;kg/m^3

Now we also know that 1 kg/m3 = 0.062428 lb/ft3

901.91×0.062428=56.30  lb/ft3901.91 \times 0.062428 = 56.30 \;lb/ft^3

Answer: 56.30 lb/ft3

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