determine the sea level specific weight in lbf/cubic feet of liquid of density of 1.75 per cubic feet
We know that 1 kg/m3 = 0.00194032 slug/ft3
1.750.00194032=901.91 kg/m3\frac{1.75}{0.00194032} = 901.91 \;kg/m^30.001940321.75=901.91kg/m3
Now we also know that 1 kg/m3 = 0.062428 lb/ft3
901.91×0.062428=56.30 lb/ft3901.91 \times 0.062428 = 56.30 \;lb/ft^3901.91×0.062428=56.30lb/ft3
Answer: 56.30 lb/ft3
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