Solution.
V=25.0⋅10−3m3;
m=2.0kg;
M(Ne)=20.2⋅10−3kg/mol;
M(O2)=32⋅10−3kg/mol;
p=98.0atm=9929850Pa;
T=301K;
pV=M(Ne)m(Ne)RT⟹V=M(Ne)pm(Ne)RT;
V=20.2⋅10−3⋅99298502.0⋅8.31⋅301=0.025m−3;
p=const;T=const;
pV=M(O2)m(O2)RT⟹m(O2)=RTpVM(O2);
m(O2)=8.31⋅3019929850⋅25.0⋅10−3⋅32⋅10−3=3.2kg;
Answer: m(O2)=3.2kg.
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