A 25.0L tank contains 2.0kg of neon gas with a pressure of 98.0 atm at 28 degrees celcius. How many kilograms of oxygen can fill the tank under the same pressure and temperature?
Solution.
"V=25.0\\sdot 10^{-3}m^3;"
"m=2.0 kg;"
"M(Ne)=20.2\\sdot 10^{-3}kg\/mol;"
"M(O_2)=32\\sdot10^{-3} kg\/mol;"
"p=98.0 atm=9929850 Pa;"
"T=301K;"
"pV=\\dfrac{m(Ne)}{M(Ne)}RT\\implies V=\\dfrac{m(Ne)}{M(Ne)p}RT;"
"V=\\dfrac{2.0}{20.2\\sdot10^{-3}\\sdot9929850}\\sdot8.31\\sdot301=0.025 m^{-3};"
"p=const; T=const;"
"pV=\\dfrac{m(O_2)}{M(O_2)}RT\\implies m(O_2)=\\dfrac{pVM(O_2)}{RT};"
"m(O_2)=\\dfrac{9929850\\sdot25.0\\sdot10^{-3}\\sdot32\\sdot10^{-3}}{8.31\\sdot301}=3.2kg;"
Answer: "m(O_2)=3.2kg."
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