Answer to Question #264379 in Molecular Physics | Thermodynamics for nicole

Question #264379

A 25.0L tank contains 2.0kg of neon gas with a pressure of 98.0 atm at 28 degrees celcius. How many kilograms of oxygen can fill the tank under the same pressure and temperature?

1
Expert's answer
2021-11-11T11:58:41-0500

Solution.

V=25.0103m3;V=25.0\sdot 10^{-3}m^3;

m=2.0kg;m=2.0 kg;

M(Ne)=20.2103kg/mol;M(Ne)=20.2\sdot 10^{-3}kg/mol;

M(O2)=32103kg/mol;M(O_2)=32\sdot10^{-3} kg/mol;

p=98.0atm=9929850Pa;p=98.0 atm=9929850 Pa;

T=301K;T=301K;

pV=m(Ne)M(Ne)RT    V=m(Ne)M(Ne)pRT;pV=\dfrac{m(Ne)}{M(Ne)}RT\implies V=\dfrac{m(Ne)}{M(Ne)p}RT;

V=2.020.210399298508.31301=0.025m3;V=\dfrac{2.0}{20.2\sdot10^{-3}\sdot9929850}\sdot8.31\sdot301=0.025 m^{-3};

p=const;T=const;p=const; T=const;

pV=m(O2)M(O2)RT    m(O2)=pVM(O2)RT;pV=\dfrac{m(O_2)}{M(O_2)}RT\implies m(O_2)=\dfrac{pVM(O_2)}{RT};

m(O2)=992985025.0103321038.31301=3.2kg;m(O_2)=\dfrac{9929850\sdot25.0\sdot10^{-3}\sdot32\sdot10^{-3}}{8.31\sdot301}=3.2kg;


Answer: m(O2)=3.2kg.m(O_2)=3.2kg.


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